A `0.2 kg` object at rest is subjected to a force `(0.3hati-0.4hatj) N`. What is its velocity vector after `6 sec`

A 0.2 kg object at rest is subjected to a force (0.3hati - 0.4 hatj) Newton. What is velocity of the object after 6 second

An object with mass 5 kg is acted upon by a force, vecF = (-3hati + 4hatj) N. If its initial velocity at t = 0 is vecv = (6hati – 12hatj) m s^(-1) , the time at which it will just have a velocity along y-axis is

The velocity of an object at t =0 is vecv_(0) =- 4 hatj m/s . It moves in plane with constant acceleration veca = ( 3hati + 8 hatj) m//s^(2) . What is its velocity after 1 s?

The velocity of an object at t =0 is vecv_(0) =- 4 hatj m/s . It moves in plane with constant acceleration veca = ( 3hati + 8 hatj) m//s^(2) . What is its velocity after 1 s?

A particle of mass 2kg is moving in free space with velocity vecv_0=(2hati-3hatj+hatk)m//s is acted upon by force vecF=(2hati+hatj-2hatk)N . Find velocity vector of the particle 3s after the force starts acting.

A particle of mass 2kg is moving in free space with velocity vecv_0=(2hati-3hatj+hatk)m//s is acted upon by force vecF=(2hati+hatj-2hatk)N . Find velocity vector of the particle 3s after the force starts acting.

A particle of mass 2kg is moving in free space with velocity vecv_0=(2hati-3hatj+hatk)m//s is acted upon by force vecF=(2hati+hatj-2hatk)N . Find velocity vector of the particle 3s after the force starts acting.

A body starts with a velocity (2hati + 3hatj + 11hatk) m/s and moves with an acceleration (5hati + 5hatj - 5hatk) m//s^(2) . What is its velocity after 0.2 sec ?