If (a, 0) is a point on a diameter of the circle `x^(2)+y^(2)=4`, then the equation `x^(2)-4x-a^(2)=0` has

If (t,0) is point on diameter of circle x ^(2) + y ^(2) =4, then the equation x ^(2) - 4x - t ^(2)=0 has

If (a,0) is a point on a diameter of the circle x^2+y^2=4 , then x^2-4x-a^2=0 has

One of the diameter of the circle x^(2)+y^(2)-2x+4y-4=0 , is

The length of the diameter of the circle x^2+y^2−4x−6y+4=0

The length of the diameter of the circle x^(2)+y^(2)-4x-6y+4=0 is -

The equation of the diameter of the circle x^(2)+y^(2)+2x-4y=4=0 that is parallel to 3x+5y-4=0 is

The equation of the diameter of the circle x^(2)+y^(2)+2x-4y-4=0 that is parallel to 3x+5y-4=0 is

The equation of the diameter of the circle x^(2)+y^(2)+6 x-4 y-2=0 , passing through the point (2,-3) is

The point of tangency of the circles x^(2)+y^(2)-2x-4y=0 and x^(2)+y^(2)-8y-4=0 is

A foot of the normal from the point (4, 3) to a circle is (2, 1) and a diameter of the circle has the equation 2x -y -2 =0 . Then the equation of the circle is: