A particle is moving with velocity `v=t^(3)-6t^(2)+4`, where v is in `m//s` and t is in seconds. At what time will the velocity be maximum//minimum and what is it equal to?

A particle is moving with velocity v=4t^(3)+3 t^(2)-1 m//s . The displacement of particle in time t=1 s to t=2 s will be

A particle is moving such that s=t^(3)-6t^(2)+18t+9 , where s is in meters and t is in meters and t is in seconds. Find the minimum velocity attained by the particle.

A particle is moving such that s=t^(3)-6t^(2)+18t+9 , where s is in meters and t is in meters and t is in seconds. Find the minimum velocity attained by the particle.

A particle in moving in a straight line such that its velocity is given by v=12t-3t^(2) , where v is in m//s and t is in seconds. If at =0, the particle is at the origin, find the velocity at t=3 s .

The speed(v) of a particle moving along a straight line is given by v=(t^(2)+3t-4 where v is in m/s and t in seconds. Find time t at which the particle will momentarily come to rest.

The speed(v) of a particle moving along a straight line is given by v=(t^(2)+3t-4 where v is in m/s and t in seconds. Find time t at which the particle will momentarily come to rest.

The speed(v) of a particle moving along a straight line is given by v=(t^(2)+3t-4 where v is in m/s and t in seconds. Find time t at which the particle will momentarily come to rest.

The velocity v of a particle is given by the equation v=6t^(2)-6t^(3) , where v is in ms^(-1) , t is the instant of time in seconds while 6 and 6 are suitable dimensional constants. At what values of t will the velocity be maximum and minimum ? Determine these maximum and minimum values of the velocity.

The velocity of an object moving rectilinearly is given as a function of time by v=4t-3t^(2) where v is in m/s and t is in seconds. The average velocity if particle between t=0 to t=2 seconds is