In the reaction `2Na_(2)S_(2)O_(3)+I_(2) rarr Na_(2)S_(4)O_(6)+2NaI`, the oxidation state of S is -

In the reaction 2Na_(a)S_(2)O_(3)+I_(2) rarr Na_(2)S_(4)O_(6)+ 2NaI , the equivalent weight of Na_(2)S_(2)O_(3) (mol. Wt. =M) is equal to

In this reaction 2Na_(2)S_(2)O_(3)+I_(2)=Na_(2)SO_(4)O_(6)=2NaI_(2) acts as:

In this reaction 2Na_(2)S_(2)O_(3)+I_(2) to Na_(2)SO_(4)O_(6)+2NaI_(2) , NaI_(2) acts as:

In the reaction : 2Na_2S_2O_3 + I_2 rarr Na_2S_4O_6 +2NaI the equivalent weight of Na_2S_2O_3 is equal to :

In the reaction l_(2)+2Na_(2)S_(2)O_(3) to Na_(2)S_(4)O_(6)+2Nal the equivalent weight of oxidant is [M= Molecular weight of oxidant]-

The equivalent of iodine in the reaction 2Na_(2)S_(2)O_(3)+I_(2)rarr 2NaI+Na_(2)S_(4)O_(6) is [M is molecular weight]

The equivalent weight of Na_(2)S_(2)O_(3) ( Mol. wt = M ) in the reaction , 2Na_(2)S_(2)O_(3) + I_(2) rarr Na_(2) S_(4)O_(6) + 2NaI is-