A particle is projected vertically upward from the ground at time `t = 0` and reaches a height `h` at `t = T`. Show that the greater height of the particle is `(g T^(2) + 2h)^(2)//8 gT^(2)`

A particle when projected vertically upwards from the ground, takes time T to reach maximum height H. Find out (i) The height of the particle from ground at T//2,2T//3,4T//3,5T//4 and also find the ratio of K.E. to P.E. for particle at the same instant of time. (ii) If the particle crosses a point at height 7H//16 at time t_(1) and t_(2) then find t_(1)//t_(2)

A particle is projected vertically upwards and it reaches maximum height H in time T seconds. What is the height of particle at any time t.

A particle is projected vertically upwards and it reaches the maximum height H in time T seconds. The height of the particle at any time t will be-

A particle is projected vertically upwards and it reaches the maximum height H in time T seconds. The height of the particle at any time t will be-

A particle is projected vertically upwards and it reaches the maximum height H in time T seconds. The height of the particle at any time t will be-

A particle is projected vertically upwards and reaches the maximum height H in time T. The height of the partlcle at any time t (lt T) will be

A particle is projected vertically upwards and reaches the maximum height H in time T. The height of the partlcle at any time t (lt T) will be

A particle is projected vertically upwards from a point O on the ground. It takes time t_(1) to reach a point A at a height h above the ground, it continues to move and takes a time t_(2) to reach the ground. Find (a) h, (b) the maximum height reached and (c ) the velocity of the partical at the half of maximum height.

A particle is projected vertically upwards and is at a height h after t_(1) seconds and again after t_(2) seconds then