If `sin(x+20^0)=2sinxcos40^0,w h r ex in (0,pi/2),` then which of the following hold(s) good? `cos2x=1/2` (b) `cos e c4x=2` `secx/2=sqrt(6)-sqrt(2)` (d) `tanx/2=(2-sqrt(3))`

If sin(x+20^0)=2sinxcos40^0,where in (0,pi/2), then which of the following hold(s) good? (a) cos2x=1/2 (b) cos e c4x=2 (c) secx/2=sqrt(6)-sqrt(2) (d) tanx/2=(2-sqrt(3))

If sin(x+20^0)=2sinxcos40^0,where in (0,pi/2), then which of the following hold(s) good? (a) cos2x=1/2 (b) cos e c4x=2 (c) secx/2=sqrt(6)-sqrt(2) (d) tanx/2=(2-sqrt(3))

If sin(x+20^0)=2sinxcos40^0,where in (0,pi/2), then which of the following hold(s) good? (a) cos2x=1/2 (b) cos e c4x=2 (c) sec(x/2)=sqrt(6)-sqrt(2) (d) tan(x/2)=(2-sqrt(3))

sin(x+20^(@))=2sin x cos40^(@), where in(0,(pi)/(2)) then which of the following hold(s) good? (a) cos2x=(1)/(2)(b)cos ec4x=2(c)(sec x)/(2)=sqrt(6)-sqrt(2)(d)(tan x)/(2)=(2-sqrt(3))

If sin (x + 20^(@)) = 2 sin x cos 40^(@), where x in (0.pi //2), then which of the following hold (s) good?

If x in (0,pi/2),t h e ns howt h a t d/(dx)cos^(-1){7/2(1+cos2x)+(sqrt(sin^2x-48cos^2x))sinx} =1+(7sinx)/sqrt(sin^2-48cos^2x)

If sin^(-1)x+cot^(-1)(1/2)=pi/2,\ t h e n\ x is 0 b. 1/(sqrt(5)) c. 2/(sqrt(5)) d. (sqrt(3))/2

A solution of sin^-1 (1) -sin^-1 (sqrt(3)/x^2)- pi/6 =0 is (A) x=-sqrt(2) (B) x=sqrt(2) (C) x=2 (D) x= 1/sqrt(2)

A solution of sin^-1 (1) -sin^-1 (sqrt(3)/x^2)- pi/6 =0 is (A) x=-sqrt(2) (B) x=sqrt(2) (C) x=2 (D) x= 1/sqrt(2)

lim_(x rarr0)(sin^(2)x)/(sqrt(2)-sqrt(1+cos x))=(A)sqrt(2)(B)2(C)