The equation of the tangent to the parabola `y^(2)=8x` and which is parallel to the line x-y+3=0 is

The equation of the tangent to the parabola y^(2) = 8x, which is parallel to the line 2x-y+7=0 ,will be

The equation of the tangent to the parabola y^(2) = 4x + 5 which is parallel to the line y= 2x + 7 is-

The equation of the tangent to the parabola (y-2)^(2)=8(x+1), which is parallel to the line y=2 x-3 is

The equation of the tangent to the parabola y^(2)=8x which is perpendicular to the line x-3y+8=0 , is

The equation of the tangent to the parabola y^(2)=8x which is perpendicular to the line x-3y+8=0 , is

Find the equation of the tangent to the parabola y^(2) = 8x which is parallel to the line 2x + 2y + 5 = 0 . Find its point of contact.

The equation of the tangent to the parabola y^(2) = 8x which is perpendicular to the line x-3y+8=0 is -

Find the equation of the tangents to the parabola 3y^(2)=8x , parallel to the line x-3y=0 .