25 mL, 0.2 M `Ca(OH)_2` is neutralised by 10 mL of 1 M HCl. then pH of resulting solution is-

At 90^(@) C, pure water has [H^(+)]=10^(-6) M.If 100 mL of 0.2 M HCl is added to 200 mL of 0.1 M KOH at 90^(@) C then pH of the resulting solution will be :

At 90^(@) C, pure water has [H^(+)]=10^(-6) M.If 100 mL of 0.2 M HCl is added to 200 mL of 0.1 M KOH at 90^(@) C then pH of the resulting solution will be :

At 90^(@) C, pure water has [H^(+)]=10^(-6) M.If 100 mL of 0.2 M HCl is added to 200 mL of 0.1 M KOH at 90^(@) C then pH of the resulting solution will be :

100 ml of 0.15 M HCl is mixed with 100 ml of 0.05 M HCl, is the pH of the resulting solution?

50 mL of 0.1 M HCl and 50 mL of 2.0 M NaOH are mixed. The pH of the resulting solution is

50 ml of 0.1 M HCl and 50 ml of 0.2 M NaOH are mixed. The pH of the resulting solution is :

50 ml of 0.2 M NH_(4)OH and 50 ml of 0.2 M HCl solutions are Mixed. pH of the resulting solution is (Given Kb of NH_(4)OH=1 times 10^(-5) )

150 ml of 0.5 HCl and 100 ml of 0.2 M HCl are mixed. Find the pH of the resulting solution.