The equation of the circle drawn with the focus of the parabola `(x – 1)^(2) - 8y = 0` as its centre and touching the parabola at its vertex is

The equation of the circle drawn with the focus of the parabola (x-1)^(2)-8y=0 as its centre touching the parabola at its vertex is:

If a circle drawn with radius 1 unit and whose centre is the focus of the parabola y^(2)=4x touches the parabola at

Equation of a circle which touches the parabola y^(2)-4x+8=0, at (3,2) and passes through its focus is

A circle of radius 4 drawn on a chord of the parabola y^(2)=8x as diameter touches the axis of the parabola. Then the slope of the chord is

A circle of radius 4 drawn on a chord of the parabola y^(2)=8x as diameter touches the axis of the parabola. Then the slope of the chord is

Let a circle touches to the directrix of a parabola y ^(2) = 2ax has its centre coinciding with the focus of the parabola. Then the point of intersection of the parabola and circle is

Let a circle touches to the directrix of a parabola y ^(2) = 2ax has its centre coinciding with the focus of the parabola. Then the point of intersection of the parabola and circle is

A chord is drawn through the focus of the parabola y^(2) =6x such that its distance from the vertex of this parabola is (sqrt5)/(2) , then its slope can be