ABCD is a square with side a. If AB and AD are taken as coordiate axes. Then the equation of the circle circumseribing the square is.

ABCD is a square with side a. If AB and AD are taken as positive coordinate axes then equation of circle circumscribing the square is

ABCD is a square with side a. If AB and AD are taken as positive coordinate axes then equation of circle circumscribing the square is

ABCD is a square of side 'a'. If AB and AD are taken as co-ordinate axes, prove that the equation of the circle circumscribing the square is x^2+y^2=a(x+y) .

ABCD is a square whose side is a. Taking AB and AD as axes, find the equation of the circle circumscribing the square.

ABCD is a rectangle with sides AB=p,BC=q. If AB and AD are taken as negative directions of coordinate axes,then the equation of the circle circumscribing the rectangle is

ABCD is a rectangle with sides AB=p,BC=q. If AB and AD are taken as negative directions of coordinate axes,then the equation of the circle circumscribing the rectangle is

ABCD is a rectangle wih sides AB=p, BC=q,. If AB and AD are taken negative directions of coordinate axes. then the equaton of the circumscribing the rectangle is

ABCD is a rectangle wih sides AB=p, BC=q,. If AB and AD are taken negative directions of coordinate axes. then the equaton of the circumscribing the rectangle is

ABCD is a square 2a unit. Taking AB and AD as axes of coordinates, the equation to the circle which touches the sides of the square is