Sulphide ion `(S^(2-))` reacts with solid sulphur forming `S_(2)^(2-)` and `S_(3)^(2-)` with formation constants 12 and 132 respectively. Formation constant of `S_(3)^(2-)` from sulphur and `S_(2)^(2-)` is `:`

The oxidation number of sulphur in S_(2)F_(2) and S_(8) is

Oxidation number of sulphur in S_(2)SO_(3)^(2-) is

Sulphide ions in alkaline solution react with solid sulphur to form polyvalent sulphide ions. The equilibrium constant for the formation of S_(2)^(2-) and S_(3)^(2-) from S and S^(2-) ions is 1.7 and 5.3 respectively. Calculate equilibrium constant for the formation of S_(3)^(2-) from S_(2)^(2-) and S .

Sulphide ions in alkaline solution react with solid sulphur to form polyvalent sulphide ions. The equilibrium constant for the formation of S_(2)^(2-) and S_(3)^(2-) from S and S^(2-) ions is 1.7 and 5.3 respectively. Calculate equilibrium constant for the formation of S_(3)^(2-) from S_(2)^(2-) and S .

The two sulphur atoms in Na_(2)S_(2)O_(3) have

" Oxidation state of terminal Sulphur in S_(2)O_(3)^(-2) is "

Sulphides ions in alkaline solution react with solid sulphur to form polyvalent sulphide ions. The equillibrium constant for the formation of S_2^(2-) and S_3^(2-) from S and S^(2-) ions are 1.7 and 5.3 respectively.What is the equillibrium constant for the formation of S_3^(2-) from S_2^(2-) and S ?

What will be oxidation number of sulphur in S_2O_(8)^(2-) ion and S_(4)O_(6)^(2-) ion ?

Oxidation number of sulphur in S_(8), S_(2)F_(2) and H_(2)S are