Two bodies of masses `M_(1)` and `M_(2)`, are placed at a distance `R` apart. Then at the position where the gravitational field due to them is zero, the gravitational potential is

Two bodies of masses m_(1) and m_(2) are placed at a distance r apart. Show that the position where the gravitational field due to them is zero, the potential is given by -G (m_(1) + m_(2) + 2 sqrt(m_(1) + m_(2)))//r

Two bodies of masses m_(1) and m_(2) ar placed at a distance r apart. Shows that the position where the gravitational field due to them is zer, the potential is given by V=-(G)/(r)"["m_(1)+m_(2)+2sqrt(m_(1)m_(2))"]"

Two bodies of masses M_(1) and M_(2) are kept separeated by a distance d. The potential at the point where the gravitational field produced by them is zero,the gravitational potential will be :-

Two bodies of masses m and M are placed at distance d apart. The gravitational potential (V) at the position where the gravitational field due to them is zero V is

Two bodies of masses m and M are placed at distance d apart. The gravitational potential (V) at the position where the gravitational field due to them is zero V is

Two bodies of masses m and M are placed at distance d apart. The gravitational potential (V) at the position where the gravitational field due to them is zero V is

Two bodies of masses m_(1) and m_(2) are placed distant d apart. Show that the position where the gravitational field due to them is zero, the potential is given by, V = - (G)/( d) ( m_(1) +m_(2) + 2 sqrt( m_(1) m_(2)))