If the earth is a point mass of `6xx10^(24)` kg revolving around the sun at a distance of `1.5xx10^(8)` km and in time `T = 3.14 xx10^(7)s`. then the angular momentum of the earth around the sun is

If the earth is a point mass of 6 xx 10^(24) kg revolving around the sun at a distance of 1.5 xx 10^(8) km and in time, T = 3.14 xx 10^(7)s , then the angular momentum of the earth around the sun is

If the earth is a point mass of 6 xx 10^(24) kg revolving around the sun at a distance of 1.5 xx 10^(8) km and in time, T = 3.14 xx 10^(7)s , then the angular momentum of the earth around the sun is

If the earth is a point mass of 6 xx 10^(24) kg revolving around the sun at a distance of 1.5 xx 10^(8) km and in time T = 3.14 xx 10^(7) s, then the angular momentum of the earth around the sun is

Suppose earth is a point mass of 6 xx 10^(24) kg revolving around the sun in a circular orbit of diameter 3xx10^(8) km in time 3.14 xx 10^(7) s . What is the angular momentum of the eart around the sun ?

The earth of mass 6xx10^(24)kg revolves round the sun with angular velocity 3xx10^(-7)"rad/s" in a circular orbit of radius 1.5xx10^(8)km. Then the force exerted by the sun on the earth in newtons, is

The earth (mass = 6 xx 10^(24) kg) revolves around the sun with an angular velocity of 2 xx 10^(-7) rad/s in a circular orbit of radius 1.5 xx 10^8 km. The force exerted by the sun on the earth, in newton, is .........

The earth (mass= 6 xx 10^24 kg) revolves around the Sun with angular velocity 2 xx 10^-7 rad//s in a circular orbit of radius 1.5 xx 10^8 km. The force exerted by the Sun on the earth in Newton is