If normal to hyperbola `x^2/a^2-y^2/b^2=1` drawn at an extremity of its latus-rectum has slope equal to the slope of line which meets hyperbola only once, then the eccentricity of hyperbola is

The normla to the hyperbola (x^2)/(a^2)-(y^2)/(b^2)=1 drawn at an extremity of its latus rectum is parallel to an asymptote. Show that the eccentricity is equal to the square root of (1+sqrt(5))//2.

The eccentricity of the hyperbola x^2/a^2-y^2/b^2=1 if the length of its latus rectum is equal to length of its semi conjugate axis, is:

If the latus rectum of a hyperbola is equal to half of its transverse axis, then its eccentricity is -

Let L L ' be the latus rectum through the focus of the hyperbola (x^2)/(a^2)-(y^2)/(b^2)=1 and A ' be the farther vertex. If A ' L L ' is equilateral, then the eccentricity of the hyperbola is (axes are coordinate axes).

If the latus rectum subtends a right angle at the center of the hyperbola (x^2)/(a^2)-(y^2)/(b^2)=1 , then find its eccentricity.

If the latus rectum subtends a right angle at the center of the hyperbola (x^2)/(a^2)-(y^2)/(b^2)=1 , then find its eccentricity.

If the latus rectum subtends a right angle at the center of the hyperbola (x^2)/(a^2)-(y^2)/(b^2)=1 , then find its eccentricity.

The eccentricity of the hyperbola whose latus rectum is equal to half of its conjugate axis is

The eccentricity of the hyperbola whose latus rectum is equal to half of its transverse axis is