If `pv=81," then "(dp)/(dv)" at "v=9` is equal to

If pv=81 then (dp)/(dv) at v=3 is

If v = log ( 1 + x^(2)) and u = x - tan^(-1) x then ,( du)/( dv) is equal to

If 2t= v^(2) then (dv)/(dt) = …….

Let v and a be the instantaneous velocity and acceleration of a particle moving in a plane. Then rate of change of speed (dv)/(dt) of the particle is equal to

Let v and a be the instantaneous velocity and acceleration of a particle moving in a plane. Then rate of change of speed (dv)/(dt) of the particle is equal to

If e^(v)+e^(u)=e^(v+u) , then (du)/(dv)=

The value of tan 81^(@) - tan 63^(@) - tan 27^(@)+ tan 9^(@) is equal to

The vlaue of tan 81^(@) - tan 63^(@) - tan 27^(@)+ tan 9^(@) is equal to

The Speed Of a particle moving in a plane is equal to the magnitude of its instantaneous velocity, v=|vl= sqrt(v_x^2+v_y^2). (a) Show that the rate of change of the speed is (dv)/(dt)=(v_xa_x+v_ya_y)/(sqrt(v_x^2+v_y^2)) . (b) Show that the rate of change of speed can be expressed as (dv)/(dt) is equal to a_t the component of a that is parallelto v.

The Speed Of a particle moving in a plane is equal to the magnitude of its instantaneous velocity, v=|vl= sqrt(v_x^2+v_y^2). (a) Show that the rate of change of the speed is (dv)/(dt)=(v_xa_x+v_ya_y)/(sqrt(v_x^2+v_y^2)) . (b) Show that the rate of change of speed can be expressed as (dv)/(dt) is equal to a_t the component of a that is parallelto v.