if `x+y=9 , x^2+y^2=41 ,` then `x^3+y^3=?`

If x-y=1 and x^(2)+y^(2)=41, then the value of x+y will be (a)5 or 4(b)-5 or -4 (c) +-9(d)+-1

If x - y = 9 , then (x - y/3)-(y-x/3) =

If 9x^(2)+y^(2)+6x=2y-2 then 3x+y is

If (5x+2y) : (10x+3y) = 5:9 , then (2x^2+3y^2 ):(4x^2+9y^2) =? यदि (5x+2y) : (10x+3y) = 5:9 , है, तो (2x^2+3y^2 ): (4x^2+9y^2) =?

Draw the rough sketch and find the area of the region : {(x, y) : 9 x^2 + y^2 le 9, 3 x + y ge 3} .

Add : x^(3) - x^(2)y + 5xy^(2) + y^(3) , -x^(3) - 9xy^(2) + y^(3), 3x^(2)y + 9xy^(2)

If 9x^2+y^2=37 and xy = 2 , x, y> 0 , then the value of (27x^3+y^3) is : यदि 9x^2+y^2=37 और xy = 2 , x, y> 0 , तो (27x^3+y^3) का मान ज्ञात कीजिए ।

Verify : (i) x^3+y^3=(x+y)(x^2-x y+y^2) (ii) x^3-y^3=(x-y)(x^2+x y+y^2)