A disc of moment of inertia `9.8//pi^(2)kg m^(2)` is rotating at 600 rpm. If the frequency of rotation changes from 600 rpm to 300 rpm, then what is the work done ?

A disc of moment of inertia 9.8/(pi^2)kgm^2 is rotating at 600 r.p.m. If the frequency of rotation changes from 600 r.p.m. to 300 r.p.m., then what is the work done? A. 1470J B. 1452J C. 1567J D. 1632J

Moment of inertia of a plate,is 40 kgm^2 . How much work to be done to change its angular velocity from 60 rpm to 150 rpm.

Theangular speed of a car increases from 600 rpm to 1200 rpm in 10 s .What is the angular acceleration of the car ?

A wheel of diameter 20 cm is rotating 600 rpm. The linear velocity of particle at its rim is

A wheel of diameter 20 cm is rotating 600 rpm. The linear velocity of particle at its rim is

A disc of mass 2 kg and diameter 2 m is performing rotational motion. Find the work done, if the disc is rotating from 300 r.p.m. to 600 r.p.m., is

A wheel of mass 10 kg and radius of gyration 25 cm is rotating at 600 rpm. What is its moment of inerta ?

A uniform disc of moment of inertia 1 kg m^2 rotates with a speed of 120 rpm, Calculate the torque required to stop the disc in 10 revolutions ?

A flywheel of diameter 1 m is rotating at 600 r.p.m., the acceleration of a point on the rim of the fly wheel is