A non-conducting ring of radius R has charge Q distributed unevenly over it. If it rotates with an angular velocity `omega` the equivalent current will be:

A nonconducting ring of radius R has charge Q distributed unevenly over it. If it rotates with an angular velocity omega , the equivalent current will be

A conducting ring of radius R has charge Q distributed unevenly over it. If it rotates with an angular velocity omega , the equivalent current will be

A non-conducting ring of radius r has charge q distributed unevenly over it. What will be the equivalent current if it rotates with an angular velocity Omega ?

As shown in figure there is a ring having radius R and charge q distributed uniformly over it. If ring is rotated with a constant angular velocity @, then torque acting on the ring due to magnetic force is (Assume that magnetic field B is parallel to plane of ring)

A non conducting ring of radius R is charged as shown in figure : Figure

A thin disc of radius R and mass M has charge q uniformly distributed on it. It rotates with angular velocity omega . The ratio of magnetic moment and angular momentum for the disc is

A ring of radius 'r' and mass per unit length 'm' rotates with an angular velocity 'omega' in free space then :