The atomic mass of `Al^(27)` is 26.9815 amu . The mass of electron is 0.0005498 amu . The rest mass energy of `Al^(27)` nucleus is

The mass of an electron in amu is

The mass of an electron in amu is

Consider the beta^(-) decay of ._(12)^(27)Mg ._(12)^(27)Mgrarr._(13)^(27)Al^(*)+._(-1)^(0)e+vecv The atomic masses of Mg^(27) and Al^(27) are 26.98434u and 26.98154u respectively. Mass of electron is 0.00055u. The Al^(+) nucleus has excitively. Mass of electron is 1.015MeV. (a) Find the Q value of the beta^(-) decay. (b) What is maximum possible kinetic energy of emitted beta^(-) particle? (c) Find the smallest wavelenght photon that Al^(+) can emit when it de-excites. (d) As an alternative to gamma decay, the excited Al^(+) nucleus returns to its ground state by giving up its excitation energy to an atomic electron which has a binding energy of 2300eV. The process is known as internal conservation. Find the kinetic energy of the emitted electron.

The mass defect in a nucleus is 3.5 "amu" . Then the binding energy of the nucelus is

The atomic mass of B^(10) is 10.811 amu . Find the binding energy of B^(10) nucleus . The mass of electron is 0.0005498 amu. The mass of proton is m_(p) = 1.007276 amu . The mass of neutron is m_(n) = 1.008665 amu.

The nuclear mass of ""_(13)Al^(26) is 26.9815 amu. Find its nuclear density.

The atomic mass of .^(16)O is 15.995 amu while the individual masses of proton and neutron are 1.0073 amu and 1.0087 amu respectively. The mass of electron is 0.000548 amu. Calculate the binding energy of the oxygen nucleus.

The aromic mass of .^(16)O is 15.995 amu while the individual masses of proton and neutron are 1.0073 amu and 1.0087 amu respetively. The mass of electron is 0.000548 amu. Calculate the binding energy of the oxygen nucleus.