The emf of a cell is 6 V and internal resistance is `0.5 kOmega`. What will be the reading (in volt) of a voltmeter having an internal resistance of `2.5kOmega`?

The emf of a cell having internal resistance is

The emf of a cell is 6 V and internal resistance is 0.5 kOmega The reading of a Voltmeter having an internal resistance of 2.5 kOmega is

The emf of a cell is 6 V and internal resistance is 0.5 kOmega The reading of a Voltmeter having an internal resistance of 2.5 kOmega is

A voltmeter has a resistance 30 Omega . What will be its reading, when it is connected across a cell of emf 2 V having internal resistance 10 Omega ?

A voltmeter has a resistance of 100 Omega . What will be its reading when it is connected across a cell of emf 2 V and internal resistance 20 Omega ?

In a potentiometer circuit, the emf of driver cell is 2V and internal resistance is 0.5 Omega . The potentiometer wire is 1m long . It is found that a cell of emf 1V and internal resistance 0.5 Omega is balanced against 60 cm length of the wire. Calculate the resistance of potentiometer wire.

In a potentiometer circuit, the emf of driver cell is 2V and internal resistance is 0.5 Omega . The potentiometer wire is 1m long . It is found that a cell of emf 1V and internal resistance 0.5 Omega is balanced against 60 cm length of the wire. Calculate the resistance of potentiometer wire.

The emf of a battery is 6.0 V and its internal resistance is 1.5 Omega . Its potential differences is measured by a voltmeter of resistance 1000 Omega . Calculate the percentage error in the reading of emf shown by voltmeter.