A straight line through the point (2, 2) intersects the lines `sqrt(3)x+y=0` and `sqrt(3)x-y=0` at the points A and B. The equation to the line AB so that the triangle OAB is equilateral is

A st. line through the point (2, 2) intersects the lines sqrt(3)x+y=0 and sqrt(3)x-y=0 at the points A and B. The equation to the line AB so that the triangle OAB is equilateral is :

A straight line through the point (2, 2) intersects the lines sqrt3x + y = 0 and sqrt3 x-y=0 at the points A and B. The equation to the line AB so that the triangle OAB is equilateral is ,

A straight line through the point (2, 2) intersects the lines sqrt(3)x+y=0 and sqrt(3)x-y=0 at the points A and B. The equation of the line AB so that DeltaOAB is equilateral, is:

A straight line through the point (2, 2) intersects the lines sqrt3 x + y = 0 and sqrt3 x - y = 0 at the points A and B. The equation of AB so that the triangle OAB is equilateral, where O is the origin.

A straight line through the point (2,2) intersects the lines sqrt(3)x+y=0 and sqrt(3)x-y=0 at the point A and B respectively.Then find the equation of the line AB so that triangle OAB is equilateral.

A straight line through the point (2,2) intersects the lines sqrt(3)x+y=0 and sqrt(3)x-y=0 at the point A and B , respectively. Then find the equation of the line A B so that triangle O A B is equilateral.

A straight line through the point (2,2) intersects the lines sqrt(3)x+y=0 and sqrt(3)x-y=0 at the point A and B , respectively. Then find the equation of the line A B so that triangle O A B is equilateral.

A straight line through the point (2,2) intersects the lines sqrt(3)x+y=0 and sqrt(3)x-y=0 at the point A and B , respectively. Then find the equation of the line A B so that triangle O A B is equilateral.