If the length of a simple pendulum is decreased by 2%, find the percentage decrease in its period T, where `T = 2pi sqrt((l)/(g))`

If the length of a simple pendulum is decreased by 2%, find the percentage error in its period T.

If the length of a simple pendulum is decreased by 3%, then the percentage error in its period T is

The length of a simple pendulum is decreased by 21% . Find the percentage change in its time period.

The length of a simple pendulum is decreased by 21% . Find the percentage change in its time period.

If the length of a simple pendulum is increased by 2%, then the time period

If the length of a simple pendulum is increased by 2%, then the time period

If the length of a seconds pendulum is decreased by 2% find the gain or loss per day.

Assertion : The length of a simple pendulum is increases by 4% the corresponding decrease in time period will be 2% Reason : T = prop sqrt(1)

A simple pendulum is executing simple harmonic motion with a time period T. If the length of the pendulum is increased by 21%, the percentage increase in the time period of the pendulum of is