A particle moved from position `vec r_(1) = 3 hati + 2 hatj - 6 hatk `to position`vecr_(2) = 14 hati + 13 hatj +9 hatk` undre the action of a force `(4 hati + hatj +3 hatk)` newtons . Find the work done .

A particle moves from position r_1=(3hati+2hatj-6hatk) m to position r_2=(14hati+13hatj+9hatk) m under the action of a force (4hati+hatj-3hatk) N , then the work done is

A particle moves from position r_1=(3hati+2hatj-6hatk) m to position r_2=(14hati+13hatj+9hatk) m under the action of a force (4hati+hatj-3hatk) N , then the work done is

a particle moves from position vector (3 hati + 2 hat j-6hatk) to the position vector (14hati+13hatj+9hatk) in metres under the action off a constant force of (4hati+hatj+3hatk) newton.Calculate the worrk done by the force.

A particle moves from position vecr_1=2hati+3hatj to position vecr_2=3hati+7hatj , under the action of a force (10 hati+13hatj) N Calculate the work done.

A particle moves from one position vector (3hati+2hatj-6hatk) to the position vector (14hati+13hatj+9hatk) in meter when a unifrom force (4hati+hatj+3hatk) Nacts on it.Calculate the work done .