`(1)/((x + 1)^(2) - 25) `

Solve for x (1)/( 2x -3) + (1)/(x -5) =1," " x ne 3/2,5

If x+ (1)/(x)= -1 find x^(25) + (1)/(x^(25))= ?

(x-1)/(x^(2)+5x)-(x+1)/(x^(2)-25)

If 5^(1+x) + 5^(1-x) , ( a)/(2), 25^(x) + 25^(-x) are in A.P., then the set of values of a for such an A.P. to exists is :

(8)/(sqrt(1 - (4 x)^(2))) + (27)/(sqrt(1 - 9 x^(2))) - (15)/(1+ 25 x^(2))

If x+(1)/(x)=5, then x^(2)+(1)/(x^(2))=25 (b) 10 (c) 23 (d) 27

The equation of the ellipse having a vertex at (6,1) a focus at (4,1) and the eccentricity (3)/(5) is 1) ((x-1)^(2))/(16)+((y-1)^(2))/(25)=1 (2) ((x-1)^(2))/(25)+((y-1)^(2))/(16)=1 3) ((x+1)^(2))/(25)+((y+1)^(2))/(16)=1 (4) ((x+1)^(2))/(16)+((y+1)^(2))/(25)=1