A black body has maximum wavelength `lambda_(m)` at temperature `2000 K`. Its corresponding wavelength at temperature 3000 will be

A rectangular body has maximum wavelength lambda_(m) at 2000 K . Its corresponding wavelength at 3000 K will be

A black body has maximum wavelength lamda_(m) at 2000 K. Its corresponding wavelength at 3000 K will be . . . . . ..

A black body has maximum omega. L.lambda m at 2000K.Its corresponding omega .L. at 3000 K is

A black body emits maximum radiation of wavelength lambda_(1) at a certain temperature T_(1) . On increasing the temperature, the total energy of radiation emitted is increased 16 times at temperature T_(2) . If lambda_(2) is the wavelength corresponding to which maximum radiation is emitted at temperature T_(2) . Calculate the value of ((lambda_(1))/(lambda_(2))) .

A black body emits maximum radiation of wavelength lambda_(1) at a certain temperature T_(1) . On increasing the temperature, the total energy of radiation emitted is increased 16 times at temperature T_(2) . If lambda_(2) is the wavelength corresponding to which maximum radiation is emitted at temperature T_(2) . Calculate the value of ((lambda_(1))/(lambda_(2))) .

A black body emits maximum radiation of wavelength is lambda_1 = 2000 Å at a certain temperature T_1 . On increasing the temperature, the total energy of radiation emitted is increased 16 times at temperature T_2 .If lambda_2 is the wavelength corresponding to which maximum radiation emitted at temperature T_2 Calculate the value of (lambda_1/lambda_2)