`A(a,b)` and `B(0,0)` are two fixed points. If `M_1` is the mid point of `bar(AB), M_2` is mid point of `bar(AM_1), M_3` is mid point of `bar(AM_2)` and so on then `M_5` is

A(a,b) and B(0,0) are two fixed points.If M_(1) is the mid point of bar(AB),M_(2) is mid point of bar(AM_(1)),M_(3) is mid point of AM_(2) and so on then M_(5) is

A(a, b) and B(0, 0) are two fixed points. M_(1) is the mid point of AB. M_(2) is the midpoint of bar(AM_(1)), M_(3) is the midpoint of bar(AM_(2)) and so on. Then M_(5) is

Verify whether D is the mid point of bar (AG) .

Let A (a,b) be a fixed point and O be the origin of coordionates. If A_(1) is the mid-point of OA, A_(2) is the mid- poind of A A_(1),A_(3) is the mid-point of A A_(2) and so on. Then the coordinates of A_(n) are

Let A (a,b) be a fixed point and O be the origin of coordionates. If A_(1) is the mid-point of OA, A_(2) is the mid- poind of A A_(1),A_(3) is the mid-point of A A_(2) and so on. Then the coordinates of A_(n) are

Verify, whether D is the mid point of bar(AG) .

If A(-2,50,B(3,1) and P,Q are the points of trisection of bar(AB), then mid point of bar(PQ) is

Point M is the mid point of seg AB. If AB = 8 then find the length of AM.

If B is the mid point of bar (AC) and C is the mid point of bar(BD) where A,B,C,D lie on a straight line ,say why AB=CD ?

In the fig. BM=BN, M is the mid point of AB and N is the mid point of BC. Show that AB=BC