If `x+y=3-cos 4 theta` and `x-y=4sin 2 theta`,the value of `sqrtx+sqrty` is equal to

If x+y=3-cos4 theta and x-y=4sin2 theta then

x+y=3-cos4 theta and x-y=4sin2 theta then

If x +y= 3-cos4theta and x-y=4sin2theta then

If x +y= 3-cos4theta and x-y=4sin2theta then

The radius of the circle whose equation is given parametrically as x=3sin theta-4cos theta and y=3cos theta+4sin theta , theta belongs to R is equal to

If sin^(4)x+cos^(4)y+2=4sin x cos y then the value of sin x+cos y is equal to

If x sin^(3) theta + y cos^(3) theta = sin theta cos theta and x sin theta = y cos theta , then the value of x^(2) + y^(2) is :

If x = 2, y = 3 and z = 6 , then find the value of (3sqrtx)/(sqrty + sqrtz) - (4 sqrty)/(sqrtz + sqrtx) + (sqrtz)/(sqrtx + sqrty)