समीकरणों `x + ay = 0, az + y= 0` और `ax + z = 0` के अनन्त हल हों, तब a का मान होगा .

यदि x^(2)+2=0 हो तो x का मान होगा-

If x + y + z = 0 , then the value of (x^2+y^2 +z^2) div (z^2-xy) is : यदि x + y + z = 0 है, तो (x^2+y^2 +z^2) div (z^2-xy) का मान क्या होगा ?

If x, y, z are not all zero & if ax + by + cz=0, bx+ cy + az=0 & cx + ay + bz = 0 , then prove that x: y : z = 1 : 1 : 1 OR 1 :omega:omega^2 OR 1:omega^2:omega , where omega is one ofthe complex cube root of unity.

If x, y, z are not all zero & if ax + by + cz=0, bx+ cy + az=0 & cx + ay + bz = 0 , then prove that x: y : z = 1 : 1 : 1 OR 1 :omega:omega^2 OR 1:omega^2:omega , where omega is one ofthe complex cube root of unity.

If x, y, z are not all zero & if ax + by + cz=0, bx+ cy + az=0 & cx + ay + bz = 0 , then prove that x: y : z = 1 : 1 : 1 OR 1 :omega:omega^2 OR 1:omega^2:omega , where omega is one ofthe complex cube root of unity.

The system of equations ax + y + z = 0 , -x + ay + z = 0 and - x - y + az = 0 has a non-zero solution if the real value of 'a' is

The system of equation ax − y − z = a − 1 , x − ay − z = a − 1 , x − y − az = a − 1 has no solution if a is,

If a !=b , then the system of equation ax + by + bz = 0 bx + ay + bz = 0 and bx + by + az = 0 will have a non-trivial solution, if