किसी त्रिभुज ABC में यदि `b+c=3a`, तो `"cot"(B)/(2)"cot"(C )/(2)=`

In /_ABC, if 3a=b+c, then cot((B)/(2))cot((C)/(2))=

In Delta ABC , if a=3 , b=4,c=6 then ("cot" (A)/(2)+"cot" (B)/(2)+ "cot" ( C)/(2))/("cot" A + "cot" B + "cot" C)=

In Delta ABC, cot ""(A)/(2) +cot""(B)/(2) + cot""(C)/(2)=

In Delta ABC , if cot "" (A)/(2) , cot "" ( B)/(2) , cot "" (C )/(2) are in A.P., then a,b,c are in

In Delta ABC, " if" s= 2b " then " cot "" (A)/(2) cot "" ( C)/(2) =

If ina triangle ABC, b+c=3a, then cot(B/2)cot (C/2) is equal to

In /_\ABC ,3a=b+c,prove that cot(B/2).cot(C/2)=2

In a triangle ABC if b+c=3a then find the value of cot((B)/(2))cot((C)/(2))

In /_\ ABC, if 2b=a+c then cot(A/2)cot(C/2)=