. The centres of the circles `x^2 + y^2-6x-8y-7=0` and `x^2+ y^2-4x- 10y-3 = 0 `are the ends of the diameter of the circle

Find the radical axis of the circles x^2+y^2-6x-8y-3=0 and 2x^2+2y^2+4x-8y=0 .

The two circles x^2+y^2-2x-3=0 and x^2+y^2-4x-6y-8=0 are such that :

The circles x^(2)+y^(2)-6x-8y=0 and x^(2)+y^(2)-6x+8=0 are

Find the equation of the circle which cuts each of the circles x^2+y^2=4 , x^2 +y^2-6x-8y.+ 10=0 & x^2 + y^2+2x-4y-2 = 0 at the extremities of a diameter

Find the equation of the circle which cuts each of the circles x^2+y^2=4 , x^2 +y^2-6x-8y.+ 10=0 & x^2 + y^2+2x-4y-2 = 0 at the extremities of a diameter

The two circles x^(2)+y^(2)-2x-3=0 and x^(2)+y^(2)-4x-6y-8=0 are such that