`f(x)=tanx" at "x=pi/2`

show that : f(x)=tanx-cotx-x+pi/4+1 if : f'(x)=sec^2x+cosec^2x-1 and f(x)=1 , when x=pi/4 .

Let f(x)=tanx, -pi/2 and g(x)= sqrt(1-x^2) . Describe gof.

Let f(x)=[tanx[cotx]], x in [(pi)/(12),(pi)/(2)), (where [.] denotes the greatest integer less than or equal to x). The number of points, where f(x) is discontinuous is

Show that f(x)=tanx is an increasing function on (-pi//2,\ pi//2) .

Find the interval for which the function f(x) = tanx- 4 (x- 2) is increasing and decreasing in (-pi/2,pi/2) .

the function f(x)=(6/5)^((tan6x)/(tan5x)) if x is 0 to pi/2 and f(x)=b+2 if x=pi/2 and f(x)=(1+|cosx|)^{(a*|tanx|)/b} if x is pi/2 to pi Determine the values of a&b. if f is continuous at x=pi/2

The minimum value of the function f(x) =tan(x +pi/6)/tanx is:

The minimum value of the function f(x) =tan(x +pi/6)/tanx is:

Let f(x) = {((tanx - cotx)/(x-pi/4), xne pi/4),(a, x = pi/4):} . The value of 'a' so that f(x) is continuous at x = pi/4 is

Find the range of f(x) = (sinx)/(x)+(x)/(tanx) in (0,(pi)/(2))