A carnot engine has efficiency `1//5` . Efficiency becomes `1//3` when temperature of sink is decreased by 50 K What is the temperature of sink ?

A Carnot engine has an efficiency of 20% . When temperature of sink is reduced by 80°C its efficiency is doubled. The temperature of source is

A cannot engine has efficiency (1)/(6) . If temperature of sink is decreased by 62^(@)C then its efficiency becomes (1)/(3) then the temperature of source and sink:

A cannot engine has efficiency (1)/(6) . If temperature of sink is decreased by 62^(@)C then its efficiency becomes (1)/(3) then the temperature of source and sink:

A Carnot engine has an efficiency of 1//6 . When the temperature of the sink is reduced by 62^(@)C , its efficiency is doubled. The temperature of the source and the sink are, respectively.

A Carnot engine efficiency is equal to 1/7 . If the temperature of the sink is reduced by 65 K , the efficiency becomes 1/4 . The temperature of the source and the sink in the first case are respectively

A Carnot engine efficiency is equal to 1/7 . If the temperature of the sink is reduced by 65 K , the efficiency becomes 1/4 . The temperature of the source and the sink in the first case are respectively

A carnot engine has an efficiency of 30% .Its efficiency is to beincreased to 50% .By what must the temperature (in K) of the source be increased if the sink is at 300K ?