The equilibrium constant `(K_(c))` for the reaction
`2HCl(g)hArrH_(2)(g)+CL_(2)(g)`
is `4xx10^(-34)`at `25^(@)C` .what is the equilibrium constant for the reaction ?
`(1)/(2)H_(2)(g)+(1)/(2)Cl_(2)(g)hArrHCl(g)`

The equilibrium constant (K_(c)) for the reaction 2HCl(g)hArrH_(2)(g)+Cl_(2)(g) is 4xx10^(-34) at 25^(@)C .what is the equilibrium constant K_p for the reaction ?

The equilibrium constant (K_c) for the reaction 2HCl(g) iff H_2(g) + Cl_2(g) Is 4 xx 10^(-34) at 25^@C . What is the equilibrium constant for the reaction ? 1/2 H_2(g) + 1/2Cl_2(g) iff HCl(g)

The equilibrium constant K_(p) for the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) changes if:

At a given temperature, the equilibrium constant for the reaction : PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g) is 2.4xx10^(-3) . At the same temperature, the equilibrium constant for the reaction : PCl_(3)(g)+Cl_(2)(g) harr PCl_(5)(g) is :

The value of the equilibrium constant for the reaction : H_(2) (g) +I_(2) (g) hArr 2HI (g) at 720 K is 48. What is the value of the equilibrium constant for the reaction : 1//2 H_(2)(g) + 1//2I_(2)(g) hArr HI (g)

The value of the equilibrium constant for the reaction : H_(2) (g) +I_(2) (g) hArr 2HI (g) at 720 K is 48. What is the value of the equilibrium constant for the reaction : 1//2 H_(2)(g) + 1//2I_(2)(g) hArr HI (g)

If the equilibrium constant of the reaction 2HI(g)hArrH_(2)(g)+I_(2)(g) is 0.25 , find the equilibrium constant of the reaction. (1)/(2)H_(2)+(1)/(2)I_(2)hArrHI(g)

If the equilibrium constant of the reaction 2HI(g)hArrH_(2)(g)+I_(2)(g) is 0.25 , find the equilibrium constant of the reaction. (1)/(2)H_(2)+(1)/(2)I_(2)hArrHI(g)

Based on the equilibrium constant for the reaction below : 2SO_3(g)hArr2SO_2(g)+O_2(g) " " K=1.8xx10^(-5) What is the equilibrium constant for the reaction SO_2(g)+1/2O_2(g)hArr SO_3(g) " " K=?

The equilibrium constant of the reaction SO_(2)(g) + 1//2O_(2)(g)hArrSO_(3)(g) is 4xx10^(-3)atm^(-1//2) . The equilibrium constant of the reaction 2SO_(3)(g)hArr2SO_(2)(g) + O_(2)(g) would be: