A quadratic equation with integral coefficients has integral roots. Justify your answer.

The quadratic equation with real coefficients has one root 2i^(*)s

The quadratic equation with rational coefficients whose one root is 3+sqrt2 is

The quadratic equation with rational coefficients whose one root is 3+sqrt2 is

A quadratic equation with integral coefficients has two different prime numbers as its roots. If the sum of the coefficients of the equation is prime,then the sum of the roots is 2 b.5 c.7 d.11

A quadratic equation with integral coefficients has two different prime numbers as its roots. If the sum of the coefficients of the equation is prime, then the sum of the roots is a. 2 b. 5 c. 7 d. 11

A quadratic equation with integral coefficients has two different prime numbers as its roots. If the sum of the coefficients of the equation is prime, then the sum of the roots is a. 2 b. 5 c. 7 d. 11

A quadratic equation with integral coefficients has two different prime numbers as its roots. If the sum of the coefficients of the equation is prime, then the sum of the roots is 2 b. 5 c. 7 d. 11

The quadratic equation with rational coefficients whose one root is 2-sqrt(3) is

Statement -1 : There is just one quadratic equation with real coefficient one of whose roots is 1/(sqrt2 +1) and Statement -2 : In a quadratic equation with rational coefficients the irrational roots are in conjugate pairs.

Statement -1 : There is just on quadratic equation with real coefficients, one of whose roots is 1/(3+sqrt7) and Statement -2 : In a quadratic equation with rational coefficients the irrational roots occur in pair.