An iron rod of mass M and length L is cut into n equal parts by cutting it perpendicular to its length. If I is the M.I. of the rod, about an axis passing through its centre and perpendicular to its axis, then the moment of interia of each part about the similar axis

Derive an expression per the M.I. of a rectangular rod about an axis passing through its centre of mass and perpendicular to its length.

Find the expression for moment of inertia of a thin uniform rod about an axis passing through its centre and perpendicular to its length

The radius of gyration of an uniform rod of length L about an axis passing through its centre of mass and perpendicular to its length is.

The M.I. of thin uniform rod of mass 'M' and length 'l' about an axis passing through its centre and perpendicular to its length is

Moment of inertia of a thin uniform rod about an axis passing through one end and perpendicular to its length is I . Then moment of inertia of the same rod about the central axis perpendicular to its plane is

A rod of length 2 m has a mass of 0.24 kg. Its moment of inerita about an axis passing through its centre and perpendicular to the length of the rod is

Find the radius of gyration of a rod of mass 100 g and length 100 cm about an axis passing through its centre and perpendicular to its length.

The moment of inertia of a thin uniform rod of mass M and length L about an axis passing through its mid point and perpendicular to is length is 10 . Its moment of inertia about an axis passing through one of its ends and perpendicular to its ends and perpendicular to its length is

The radius of gyration of an uniform rod of length l about an axis passing through one of its ends and perpendicular to its length is.