The resistance of 0.01 M NaCl solution at 25°C is 200 ohm.The cell constant of the conductivity cell used is unity. Calculate the molar conductivity of the solution.

(a) What are the two classifications of batteries ? What is the difference between them ? (b) The resistanc of 0.01 M NaCl solution at 25^(@)C is 200Omega. The cell constant of the conductivity cell is unity. Calculate the molar conductivity of the solution.

(a) What are the two classifications of batteries ? What is the difference between them ? (b) The resistanc of 0.01 M NaCl solution at 25^(@)C is 200Omega. The cell constant of the conductivity cell is unity. Calculate the molar conductivity of the solution.

The resistance of 0.01 N solution at 25^(@)C is 200 ohm. Cell constant of the conductivity cell is unity. Calculate the equivalent conductance of the solution.

The resistance of 0.01 N solution at 25^(@)C is 200 ohm. Cell constant of the conductivity cell is unity. Calculate the equivalent conductance of the solution.

At 25^(@)C , the resistance of 0.01 N NaCl solution is 200 ohm . If cell constant of the conductivity cell is unity, then the equivalent conductance of the solution is:

The resistance of 0. 01 N NaCl solution at 25^@C is 200 Omega . Cell constant of conductivity cell is 1 cm^(-1) . The equivalent conductnance is .

0.05 "M" NaOH solution offered a resistance of 31.6 ohm in a conductivity cell at 298 K. If the cell constant of the cell is 0.367 cm^(_1) calculate the molar conductivity of the NaOH solution.

0.05M NaOH solution offered a resistance of 31.69 Omega in a conductivity cell at 298K. If the cell constant of the conductivity cell is 0.367cm^(-1) the molar conductivity of the NaOH solution is

The resistance of a 0.5 M solution of an electrolyte in a conductivity 'cell was found to be 25 ohm. Calculate the molar conductivity of the solution, if the electrodes in the cell are 1.6 cm apart and have an area of 3*2cm^(2) .

In a conductive cell, at 298K, the resistance of 0.05M NaOH solution is 31.16. Ifthe cell constant of that cell is 0.367 cm^(-1) , then calculate molar conductance of the given solution.