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In a trapezium ABCD, AB || AD and DC = 2...

In a trapezium ABCD, `AB || AD` and `DC = 2 AB`. `EF || AB`, cuts AD in F and BC in E such that `(BE)/(EC) = 3/4`. Diagonal DB intersects EF at G. Prove that, `7EF = 10AB`.

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The correct Answer is:
`11 AB`
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