Home
Class 10
MATHS
Let ABC be a triangle and D and E be two...

Let ABC be a triangle and D and E be two points on sides AB such that `AD = BE`. If `DP || BC` and `EQ || AC`, then prove that `PQ || AB`.

Text Solution

Verified by Experts

The correct Answer is:
`PS || AB`
Promotional Banner

Topper's Solved these Questions

  • TRIANGLES

    OSWAAL PUBLICATION|Exercise TOPIC-3 AREA OF SIMILAR TRIANGLES (MULTIPLE CHOICE QUESTIONS)|10 Videos
  • TRIANGLES

    OSWAAL PUBLICATION|Exercise TOPIC-3 AREA OF SIMILAR TRIANGLES (VERY SHORT ANSWER TYPE QUESTIONS)|6 Videos
  • TRIANGLES

    OSWAAL PUBLICATION|Exercise TOPIC-1 BASIC PROPORTIONALITY THEOREM (VERY SHORT ANSWER TYPE QUESTIONS)|17 Videos
  • SURFACE AREA AND VOLUMES

    OSWAAL PUBLICATION|Exercise EXERCISE 15.5|5 Videos

Similar Questions

Explore conceptually related problems

In Delta ABC , /_ B = /_C , D and E are the points on AB and AC such that BD = CE , prove that DE || BC .

D and E are points on sides AB and AC respectively of Delta ABC such that ar (DBC) = ar EBC). Prove that DE |\| BC.

In Delta ABC , DE || BC and CD || EF . Prove that AD^(2) = AF xx AB

D is a point on side BC ΔABC such that AD = AC (see figure). Show that AB > AD.

D and E are points on sides AB and AC respectively of tirangle ABC such that ar (DBC) = ar (EBC) . Prove that DE || BC

AB is line segment and P is its mid point. D and E are points on the same side of AB such that BAD = ABE and EPA = DPB show that (i) Delta DAP ~= Delta EBP (ii) AD = BE

In Delta ABC , AD is the median and PQ || BC . Prove that PE = EQ

In an equilateral triangle ABC , D is a point on side BC such that BD = 1/3 BC . Prove that 9 AD^(2)=7AB^(2) .

In an equilateral triangle ABC, D is a point on side BC such that BD = 1/3 BC . Prove that 9 AD^(2) = 7 AB^(2) .

In an equilateral triangle ABC, D is a point on side BC such that BD = (1)/(3) BC. Prove that 9 AD^(2) = 7 AB^(2) .