Home
Class 10
MATHS
In the given figure DE || BC. If AD = 1....

In the given figure `DE || BC`. If `AD = 1.5 cm`, `BD = 2AD`, then find `(ar(Delta "ADE"))/(ar("trapezium BCED"))`

Text Solution

Verified by Experts

The correct Answer is:
`1/8`
Promotional Banner

Topper's Solved these Questions

  • TRIANGLES

    OSWAAL PUBLICATION|Exercise TOPIC-3 AREA OF SIMILAR TRIANGLES (LONG ANSWER TYPE QUESTIONS)|3 Videos

  • TRIANGLES

    OSWAAL PUBLICATION|Exercise TOPIC-3 AREA OF SIMILAR TRIANGLES (LONG ANSWER TYPE QUESTIONS-(II))|2 Videos

  • TRIANGLES

    OSWAAL PUBLICATION|Exercise TOPIC-3 AREA OF SIMILAR TRIANGLES (VERY SHORT ANSWER TYPE QUESTIONS)|6 Videos

  • SURFACE AREA AND VOLUMES

    OSWAAL PUBLICATION|Exercise EXERCISE 15.5|5 Videos

Similar Questions

Explore conceptually related problems

In the figure, DE || BC , AD : AB = 1 : 2 , BC = 6 cm , then DE is :

In Delta ABC , DE || BC , If AD = 3 cm , BD = 2 cm and AE = 2.7 , then AC is equal to :

In the given figure DeltaABC, DE"||"BC . If DE=5cm, BC=8cm and AD=3.5cm , then the length of AB is

In Delta ABC , DE || BC . If AD= 5 cm , BD = 7 cm and AC = 18 cm , find the length of AE.

In the given figure , BD bot AC .Prove that AB^2 +CD^2 = AD^2 +BC^2

In the following figure DE || AB . If AD = 7 cm , CE = 10 cm and CD = 5 cm , then the length of BE =

In the given figure, AB||DC and AD||BC show that DeltaABC ~= Delta CDA .

If Delta ABC ~ Delta PQR with (BC)/(QR) = 1/3 , then find (ar Delta PRQ)/(ar Delta BCA) ?

In the given figure, AD = 3 cm, AE = 5 cm, BD = 4 cm, CE = 4 cm, CF = 2 cm, BF = 2.5 cm, then find the pair of parallel lines and hence their lengths.