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Diagonlas AC and BD of a trapezium ABCD ...

Diagonlas AC and BD of a trapezium ABCD with AB ||DC intersect each other at the point O. using a similarity criterion for two triangles, show that `(OA)/(OC) = (OB)/(OD)`.

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The correct Answer is:
`/_ OAB = /_ OCD`
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OSWAAL PUBLICATION-TRIANGLES-TEXTBOOK CORNER (EXERCISE 2.3)
  1. State which pairs of triangles in Fig are similar. Write the similarit...

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  2. In the figure given below, Delta ODC - Delta OBA, / BOC = 125^(@) and ...

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  3. Diagonlas AC and BD of a trapezium ABCD with AB ||DC intersect each ot...

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  4. In Fig . (QR)/(QS) = (QT)/(PR)and |ul(1)=|ul(2) . Show that Delta PQS...

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  5. S and T are point on sides PR and QR of Delta PQR such that / P = / RT...

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  6. In Fig. If Delta ABE = ACD , show that Delta ADE ~ Delta ABC .

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  7. In Fig. Altitudes AD and CE of Delta ABC intersect each other at th...

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  8. E is a point on the side AD produced of a parallelogram ABCD and BE in...

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  9. In Fig , ABC and AMP are two right triangles, right angled at B and M...

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  10. GD and GH are respectively the bisectors of angleACB and angleEGF suc...

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  11. In Fig E is a point on side CB produced of an isosceles triangle ABC ...

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  12. sides AB and BC and median AD of a triangle ABC are respectively prop...

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  13. D is a point on the side BC of a triangle ABC such that angleADC=angl...

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  14. side AB and AC and median AD od a triangle ABC are respectively propor...

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  15. A verticle pole of height 6m casts a shadow 4m long on the ground, and...

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  16. If AD and PM are median of triangles ABC and PQR respectively where De...

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