The mean and median of 100 observations are 50 and 52 respectively. The value of the largest observation is 100. It was later found that it is 110 not 100. Find the true mean and median.

Mean and standard deviation of 100 items are 50 and 4 respectively. The sum of all squares of the items is

The mean and variance of 7 observations are 8 and 16 respectively. If five of the observation are 2, 4, 10, 12, 14. Find the remaining two observation.

The mean and variance of eight observations are 9 and 9.25, respectively. If six of the observations are 6, 7, 10, 12, 12 and 13 , find the remaining two observations.

The mean of 100 observations is 50 and their standard deviation is 5. The sum of all squares of all the obsrervations is :

The mean and standard deviation of 20 observations are found to boe 10 and 2 respectively.On rechecking it was found that on observation 8 was incorrect.Calculate the correct mean and the standard deviation in each of the following cases.(ii)if it replaced by 12.

The mean and standard deviation of six observation are 8 and 4 respectively. If each observation is multiplied by 3, Find the new mean and new standard deviation of the resulting obervations.

If mode = 80 and mean = 110, median is

The mean and standard deviation of 100 observations were calculated as 40 and 5.1, respectively by a student who took by mistake 50 instead of 40 for one observation. What are the correct mean and standard deviation?

The median of a set of 9 distinct observations is 20.5. If each of the largest 4 observations of the set is increased by 2, then the median of the new set :