The sum of four consecutive terms which are in an arithmetic progression in 32 and the ratio of the product of the first and the last term to the product of two middle terms is 7:15 . Find the number.

The sum of four consecutive terms which are in an arithmetic progression is 32 and the ratio of the product of the first and the last term to the product to two middle terms is 7:15 . Find the number.

The sum of three consecutive terms in an arithmetic progression is 6 and their product is 120. Find the three numbers.

Find three consecutive terms in an arithmetic progression whose sum is 18 and sum of their square is 140.

The sum of first n terms of an arithmetic progression is 210 and sum of its first ( n-1) is 171 . If the first 3 then write the arithmetic progression.

The sums of n terms of two arithmetic progresssions are in the ratio (7n+1):(4n+17). Find the ratio of their nth terms

The sum o the fourth and eighth terms of arithmetic progression is 24 and the sum of the sixth and tenth terms is 44. Find the first three terms of the Arithmetic progression:

Soppose that all the terms of an arithmetic progression (AP) are natural numbers. If the ratio of the sum of the first seven terms to the sum of the first eleven terms is 6:11 and the seventh term lies between 130 and 140, then the common difference of this AP is

The sums of n terms of two arithmetic progressions are in the ratio 5n + 4 : 9n + 6. Find the ratio of their 18^(th) terms.

The third term of G.P is 9. The product if its first five terms is