[" afe "2^(n)-2^(n-1)=4" ,di "n^(n" - मा ")" माг स्या "t^(+)],[[" (A) "8," (B) "9],[" (C) "27," (D) "64]]

If A=([x,x],[x,x]) then A^(n)(n in N)= 1) ([2^nx^n,2^nx^n],[2^nx^n,2^nx^n]) 2) ([2^(n-1) x^n,2^(n-1) x^n],[2^(n-1) x^n,2^(n-1) x^n]) 3) I 4) ([2^(n) x^(n-1),2^(n) x^(n-1)],[2^(n) x^(n-1),2^(n) x^(n-1)])

lim_ (n rarr oo) (1) / (n) [(1) / (n + 1) + (2) / (n + 2) + ... + (3n) / (4n)]

If (1 ^(2) - t _(1)) + (2 ^(2) - t _(2)) + ......+ ( n ^(2) - t _(n)) =(1)/(3) n ( n ^(2) -1 ), then t _(n) is

Lim {x rarr oo} {(1+ (1) / (n ^ (2))) ^ ((2) / (n ^ (2))) (1+ (4) / (n ^ (2)) ) ^ ((4) / (n ^ (2))) ...... (1+ (n ^ (2)) / (n ^ (2))) ^ (2 (n) / (n ^ (2)))}

If (1^2-t_1)+(2^2-t_2)+......(n^2-t_n)=1/3n(n^2-1) ,then t_n is :(1) n/2 (2) n-1 (3) n+1 (4) n

In a sequence, if T_(n+1)=4n+5 , then T_n is:

If for a sequence (T_(n)), (i) S_(n) = 2n^(2)+3n+1 (ii) S_(n) =2 (3^(n)-1) find T_(n) and hence T_(1) and T_(2)