Three resistors of `5 Omega, 10 Omega` and `15 Omega` are connected in series and the combination is connected to the battery of 30 V. Ammeter and voltmeter are connected in the circuit. Draw a circuit diagram to connect all the devices in proper correct order. What is the current flowing and potential difference across 10 `Omega` resistance ?

Explanation

`R= R_(1)+R_(2)+R_(3)=30 Omega`
`I= V//R= 30//30 =1 A`
V across `10 Omega== IR_(2)=1xx10=10 V`