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An electric lamp of 24 Omega and a condu...

An electric lamp of 24 `Omega` and a conductor of 6 `Omega` are connected in parallel to a 12 V battery. Calculate :
(i) Total resistance
(ii) Total current in the circuit
Potential difference across the conductor.

Text Solution

Verified by Experts

`R_(1)= 24 Omega, R_(2) = 6 Omega, V=12 V`
(i) `R = (R_(1)R_(2))/(R_(1)+R_(2))=(6xx24)/(30)=4.8 Omega`
(ii) `I= (V)/(R)= (12V)/(4.8) =(10)/(4) A = 2.5A`
(iii) Potential difference across the conductor will be 12 V because these are joined acrolls the battery.
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