Draw a circuit diagram for a circuit consisting of a battery of five cells of 2 volts each, a 5 `Omega` resistor, a 10 `Omega` resistor and a 15 `Omega` resistor, an ammeter and a plug key, all connected in aeries. Also connect a voltmeter to record tht: potential difference across the 15 `Omega` resistor and calculate :
(i) the electric current passing through the above circuit and
(ii) potential difference across `5 Omega` resistor when the key is closed.

Explanation

(i)
10 V battery Rest components
Equivalent resistance =`R_(1)+R_(2)+R_(3)`
`=5+10+15`
`=30 Omega`
Current in the circuit `I= (V)/(R)`
`I = (10V)/(30Omega) = (1)/(3) A ` or 0.33 A
(ii) Potential difference across 5 `Omega` resistor V= IR
`=(1)/(3)A xx5 Omega`
1.67 V