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An electric iron of resistance 20Omega t...

An electric iron of resistance `20Omega` takes a current of 5A. Calculate the heat developed in 30s

Text Solution

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I= 5A ,`H= 1.5xx10^(4)J ` t = 30 s, R =?
`R= (H)/(I^(2)t) = (1.5xx10^(4))/(5xx5xx30)= (1.5xx10^(4))/(25xx30)`
`= 20 Omega`
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