Three resistors of 10 `Omega`, 15 `Omega` and 20 `Omega` are connected in series in a circuit. If the potential drop across the 15 `Omega` resistor is 3 V, find the current in the circuit and potential drop across the 10 `Omega` resistor.

Explanation

In series circuit same current flows through all the resistors.
Current through 15 `Omega` resistor
`I = (V)/(R) = (3V)/(15) = (1)/(5)`
=0.2 A
`:.` Current in the circuit `=0.2` A
`:.` Potential drop across 10`Omega` resistor is
`I =(V)/(R)`
`V= IR`
`=0.2A xx10 Omega`
=2 V