Study the following electric circuit and calculate the potential difference across ` 5 Omega` resistor.

Explanation

V=IR
R = 3+4+5 `=12 Omega`
`3=Ixx12`
`I = (3)/(12) =(1)/(4)` Ampere ,
Potential difference across `5 Omega` resistor .
V=IR
`V= (1)/(4) xx5`
`= (5)/(4) V ` or 1.25 V