Calculate the amount of heat generated when 7200 coulombs of charge is transferred in one hour through a potential difference of 50 V.

Explanation

Q = 7200 C t = 1 h `= 60xx60 = 3600s ` V= 50 V
`I = (Q)/(t) = (7200)/(3600) = 2A`
`R=(V)/(I) = (50V)/(2A)= 25 Omega`
`H = I^(2) Rt `
`= 2xx2xx25xx60xx60`
`=36xx10^(4)J ` or 360 kJ.